Question on: JSS3 Mathematics - Variations
If π¦ varies directly as π₯ and π¦=9 when π₯=6, find π¦ when π₯=12.
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Given π¦=ππ₯, substituting the given values:
9=πβ 6
Solving for π:
π=9/6=1.5
Now, find π¦ whenΒ
x=12:
π¦=1.5β 12=18
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